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Calories required to make ice to steam

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¡à Condition

¢¹ mass of ice : Im (g)
¢¹ temperature of ice : It (¡É)
¢¹ specific heat of ice : Is (cal/g¡¤¡É)
¢¹ latent heat of ice : Iw (cal/g)
¢¹ specific heat of water : Ws (cal/g¡¤¡É)
¢¹ heat of vaporization of water : Wg (cal/g)
¢¹ specific heat of steam : Ss (cal/g¡¤¡É)
¢¹ temperature of steam : St (¡É)

1) Heat required to make ice of It (¡É) to ice of 0 (¡É)
¢¹ q1 = Is*Im*(0-It)

2) Heat required to make ice of 0 (¡É) to water of 0 (¡É)
¢¹ q2 = Im*Iw

3) Heat required to make water of 0 (¡É) to water of 100 (¡É)
¢¹ q3 = Ws*Im*(100-0)

4) Heat required to make water of 100 (¡É) to steam of 100 (¡É)
¢¹ q4 = Im*Wg

5) Heat required to make steam of 100 (¡É) to steam of St (¡É)
¢¹ q5 = Gs*Im*(Gt-100)

6) Total heat required
¢¹ Q = q1+q2+q3+q4+q5 = Im*(Is*(0-It)+Iw+Ws*(100-0)+Wg+Ss*(St-100))

*** Âü°í¹®Çå[References] ***

Q = Im*((0-It)*Is+Iw+Ws*(100-0)+Wg+Ss*(St-100))
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